Just fix the same function invoke like this:
URI uri = UriComponentsBuilder
.fromUriString("https://example.com/hotels/{hotel}?q={q}")
.build("Westin", "123");
↓
URI uri = UriComponentsBuilder
.fromUriString("https://example.com/hotels/{hotel}?q={q}")
.build("Westin", "123")
.toUri(); // need to create a URI from this instance
Comment From: pivotal-cla
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Comment From: pivotal-cla
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Comment From: sbrannen
Hi @yrucrew,
Thanks for submitting your first pull request to the Spring Framework!
Please note that the org.springframework.web.util.UriComponentsBuilder.build(Object...)
method returns a URI
.
Thus, the examples you have modified were already correct.
In light of that I am closing this PR.