Gin [Question] How Do Start Server Again After Stop It?

How do I be able to stop and start the server by calling defined functions.

import (
    "context"
    "fmt"
    "net/http"
    "time"

    "github.com/gin-gonic/gin"
    "golang.org/x/sync/errgroup"
)

var server *http.Server
var appCtx context.Context

func main() {
    server = createHTTPServer(":8080")
    ctx  = appCtx

    startServer(ctx)
    time.Sleep(10*time.Second)
    stopServer()
    time.Sleep(10*time.Second)
    startServer(ctx)  // SERVER cannot start again err.ErrServerClosed!!!
}

//=======================================//
func startServer(ctx) error {
    errs, _ := errgroup.WithContext(ctx)
    errs.Go(func() error {
        if err := server.ListenAndServe(); err != nil {
            return fmt.Errorf(err.Error())
        }
        return nil
    })
    return errs.Wait()
}

func  stopServer() error {
    ctx, cancel := context.WithTimeout(context.Background(), 5*time.Second)
    defer cancel()
    if err := a.server.Shutdown(ctx); err != nil {
        fmt.Println(err)
    }
    return nil
}

func createHTTPServer(addr string) (server *http.Server) {
    router := gin.Default()

    router.GET("/", func(gCon *gin.Context) {
        gCon.JSON(http.StatusOK, gin.H{"code": http.StatusOK, "data": "", "msg": "Welcome to the GoLang HTTP Server!"})
    })

    server = &http.Server{
        Addr:    addr,
        Handler: router,
    }
    return server
}

Environments Go Version: go1.17.6 Platform: windows Architecture: amd64 Gin Version: v1.7.7

Comment From: KiddoV

Never mind! I got it working.

func  stopServer() error {
    ctx, cancel := context.WithTimeout(context.Background(), 5*time.Second)
    defer cancel()
    if err := a.server.Shutdown(ctx); err != nil {
        fmt.Println(err)
    }
        server = createHTTPServer(":8080") //Re-create server instance again after stopping the server
    return nil
}