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Reproducible Example

def f(piece):
    return DataFrame({"value": piece, "demeaned": piece - piece.mean()})

df = pd.DataFrame({'a': [1,2,3], 'b': [4, 5, 5]})
res = df.groupby('a')['b'].apply(f)
print(res.name)

Issue Description

This prints 'b'. But .name shouldn't be an attribute of DataFrame...

Expected Behavior

AttributeError: 'DataFrame' object has no attribute 'name'

Installed Versions

INSTALLED VERSIONS ------------------ commit : 3b09765bc9b141349a2f73edd15aaf4f436928bd python : 3.8.15.final.0 python-bits : 64 OS : Linux OS-release : 5.10.102.1-microsoft-standard-WSL2 Version : #1 SMP Wed Mar 2 00:30:59 UTC 2022 machine : x86_64 processor : x86_64 byteorder : little LC_ALL : None LANG : en_GB.UTF-8 LOCALE : en_GB.UTF-8 pandas : 2.0.0.dev0+759.g3b09765bc9 numpy : 1.23.5 pytz : 2022.6 dateutil : 2.8.2 setuptools : 65.5.1 pip : 22.3.1 Cython : 0.29.32 pytest : 7.2.0 hypothesis : 6.58.0 sphinx : 4.5.0 blosc : None feather : None xlsxwriter : 3.0.3 lxml.etree : 4.9.1 html5lib : 1.1 pymysql : 1.0.2 psycopg2 : 2.9.3 jinja2 : 3.0.3 IPython : 8.6.0 pandas_datareader: 0.10.0 bs4 : 4.11.1 bottleneck : 1.3.5 brotli : fastparquet : 2022.11.0 fsspec : 2021.11.0 gcsfs : 2021.11.0 matplotlib : 3.6.2 numba : 0.56.4 numexpr : 2.8.3 odfpy : None openpyxl : 3.0.10 pandas_gbq : 0.17.9 pyarrow : 9.0.0 pyreadstat : 1.2.0 pyxlsb : 1.0.10 s3fs : 2021.11.0 scipy : 1.9.3 snappy : sqlalchemy : 1.4.44 tables : 3.7.0 tabulate : 0.9.0 xarray : 2022.11.0 xlrd : 2.0.1 zstandard : 0.19.0 tzdata : None qtpy : None pyqt5 : None None

Comment From: MarcoGorelli

This was fine in 1.4.4, so I'm labelling it as a regression

Comment From: MarcoGorelli

Looks like this was caused by https://github.com/pandas-dev/pandas/pull/46623

cc @ma3da (just FYI, no blame!)

Comment From: ma3da

:ok_hand: Still, sorry for the glitch!