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Reproducible Example
import pandas as pd
import numpy as np
pd.DataFrame({'data':[np.nan,1,1,3,np.nan]}).groupby('data').cumcount(ascending=True)
Issue Description
I'm not sure if this a known or expected behavior, but pandas.DataFrame.groupby.cumcount()
returns a float and NaN
values when the groupby column contains np.nan
. This is changed behavior from past versions (compared with v.1.1.0) where the count of NaN
values was returned as an int. In both the older and current version, int
s are returned if no NaN
s are present, but the dtype returned in v.2.0.0 depends on whether or not there is a NaN
.
Expected Behavior
I think the expected behavior would be as in past versions, where all values returned are int
s, for example:
>>> pd.__version__
'1.1.0'
>>> pd.DataFrame({'data':[np.nan,1,1,3,np.nan]}).groupby('data').cumcount(ascending=True)
0 0
1 0
2 1
3 0
4 1
dtype: int64
Installed Versions
Comment From: rhshadrach
Thanks for the report. This change was highlighted here: https://pandas.pydata.org/docs/whatsnew/v1.5.0.html#using-dropna-true-with-groupby-transforms
groupby has a dropna
argument that defaults to True. As your example highlights, this argument was not being respected, and now it is. You can get the desired output by setting dropna=False
:
pd.DataFrame({'data':[np.nan,1,1,3,np.nan]}).groupby('data', dropna=False).cumcount(ascending=True)
# 0 0
# 1 0
# 2 1
# 3 0
# 4 1
# dtype: int64
Does this resolve your issue?
Comment From: mluck
Yes, that's exactly what I needed.
Thanks so much!