Code Sample
pd.to_datetime('22/12/2016')
Problem description
This fails on Python 3.6.0, but works with previous versions like 3.5.2. An exception is raised with 3.6:
ValueError: Month out of range in datetime string "22/12/2016"
The error also occurs if dayfirst=True is passed to the function.
Expected Output
2016-12-22 00:00:00
Output of pd.show_versions()
INSTALLED VERSIONS
commit: None
python: 3.6.0.final.0
python-bits: 64
OS: Linux
OS-release: 3.10.0
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8
pandas: 0.19.1
nose: None
pip: 9.0.1
setuptools: 27.2.0
Cython: None
numpy: 1.11.2
scipy: None
statsmodels: None
xarray: None
IPython: None
sphinx: None
patsy: None
dateutil: 2.6.0
pytz: 2016.10
Comment From: jorisvandenbossche
Can you update to pandas 0.19.2? This was just released two days ago with some compatibility fixes for python 3.6. In any case, I cannot reproduce this error with py3.6 / pandas 0.19.2
Comment From: jreback
(py36) bash-3.2$ ipython
Python 3.6.0 |Continuum Analytics, Inc.| (default, Dec 23 2016, 13:19:00)
Type "copyright", "credits" or "license" for more information.
IPython 5.1.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [1]: pd.__version__
Out[1]: '0.19.2'
In [3]: pd.to_datetime('22/12/2016')
Out[3]: Timestamp('2016-12-22 00:00:00')