Code Sample, a copy-pastable example if possible
>>> df = pd.DataFrame([[1,2],[3,4]])
>>> df
0 1
0 1 2
1 3 4
>>> df.rename_axis('INDEX', inplace=True)
0 1
INDEX
0 1 2
1 3 4
>>> df
0 1
0 1 2
1 3 4
>>>
Problem description
The original dataframe is not changed even if the inplace argument is supplied.
Expected Output
0 1
INDEX
0 1 2
1 3 4
Output of pd.show_versions()
INSTALLED VERSIONS
------------------
commit: None
python: 3.5.2.final.0
python-bits: 64
OS: Linux
OS-release: 4.4.0-92-generic
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8
pandas: 0.20.2
pytest: None
pip: 9.0.1
setuptools: 20.7.0
Cython: None
numpy: 1.13.0
scipy: 0.19.1
xarray: None
IPython: 6.1.0
sphinx: None
patsy: 0.4.1
dateutil: 2.6.0
pytz: 2017.2
blosc: None
bottleneck: None
tables: None
numexpr: None
feather: None
matplotlib: 2.0.2
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: 0.7.3
lxml: None
bs4: 4.4.1
html5lib: 0.9999999
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: 2.8
s3fs: None
pandas_gbq: None
pandas_datareader: None
Comment From: gfyoung
Oops...also confirmed in 0.20.3
. We're actually considering deprecating this parameter (xref #16529). That being said, I don't know if we want to do this immediately for this function.
Thus, we can either implement inplace=True
OR we deprecate inplace
immediately. @jreback ?
Comment From: TomAugspurger
Already fixed in https://github.com/pandas-dev/pandas/pull/16505 :) (xref https://github.com/pandas-dev/pandas/issues/15704)